AP Precalculus
AP Precalc 2.1–2.3: Mock Concept Check 2 (Set E)
Shared by ashtont · Oct 26, 2026 · 0 plays
A second 16-question mock of the 2.1–2.3 concept check, written like the review sheet: sequence equations and terms, depreciation, claim-and-explanation tables, growth/decay reflected, limit statements and average rate of change. About 30 minutes. Every choice has an explanation.
16 questions across 4 sections. After every answer you’ll see why each choice is right or wrong, not just the one you picked.
Sample questions
Open a question to see the answer choices and the correct answer.
An arithmetic sequence has a₃ = −8 and a₁₀ = 20. Which gives an expression for aₙ and the value of a₁₁?
- A. aₙ = −8 + 4n, and a₁₁ = 36
- B. aₙ = 20 + 4(n − 3), and a₁₁ = 52
- C. aₙ = −8 + 4(n − 3), and a₁₁ = 28
- D. aₙ = −8 + 4(n − 3), and a₁₁ = 24 ✓
Correct answer: D. D = (20 − (−8))/(10 − 3) = 28/7 = 4. Using aₙ = aₖ + d(n − k) with k = 3: aₙ = −8 + 4(n − 3), so a₁₁ = −8 + 4(8) = 24.
A geometric sequence has g₁ = 5 and g₄ = −40. What is g₈?
- A. 640
- B. −640 ✓
- C. 1280
- D. −1280
Correct answer: B. R³ = −40/5 = −8, so r = −2. Then g₈ = 5(−2)⁷ = 5(−128) = −640.
A company buys equipment for $45,000. It loses 12% of its value each year. To the nearest cent, what is it worth after 6 years?
- A. $23,747.94
- B. $39,600.00
- C. $12,600.00
- D. $20,898.18 ✓
Correct answer: D. Keeping 88% each year: V(6) = 45000(0.88)⁶ ≈ $20,898.18.
A company buys equipment for $45,000. It loses 12% of its value each year. After how many whole years will its value first be less than $20,000?
- A. 8
- B. 5
- C. 6
- D. 7 ✓
Correct answer: D. V(6) ≈ $20,898.18 and V(7) = 45000(0.88)⁷ ≈ $18,390.40, so year 7 is the first time it's under $20,000.
The number of people in line at a concert entrance can be modeled by an arithmetic sequence. After 4 minutes there are 30 people in line, and after 12 minutes there are 94. According to the model, how many people are in line after 20 minutes?
- A. 158 ✓
- B. 166
- C. 188
- D. 150
Correct answer: A. D = (94 − 30)/(12 − 4) = 8 people per minute. a₂₀ = 30 + 8(20 − 4) = 158.