AP Biology
AP Bio Unit 3 MCQ Set C Mock Progress Check
Shared by Ashton · Nov 12, 2026 · 0 plays
19 questions across 5 sections. After every answer you’ll see why each choice is right or wrong, not just the one you picked.
Sample questions
Open a question to see the answer choices and the correct answer.
Which value is the activation energy of the enzyme-catalyzed reaction?
- A. 60 kJ/mol
- B. 30 kJ/mol ✓
- C. 15 kJ/mol
- D. 45 kJ/mol
Correct answer: B. The catalyzed curve is the lower one (Curve 2). Eₐ = peak − reactants = 50 − 20 = 30 kJ/mol.
A mutation changes one amino acid far from an enzyme's active site, and the enzyme's activity drops sharply. What is the most likely explanation?
- A. The change alters folding, which changes the active site's shape ✓
- B. Amino acids far from the active site are the ones that bind substrate
- C. The mutant enzyme is now consumed in each reaction it catalyzes
- D. The mutation raises the reaction's ΔG so it can no longer happen
Correct answer: A. Structure determines function. A distant change can alter the tertiary structure (3.2.A.1).
Enzymes from bacteria that live in 80 °C hot springs still work at that temperature. Compared with human enzymes, these enzymes most likely have
- A. a higher activation energy, so heat is needed to start them
- B. more interactions holding their folded shape ✓
- C. no hydrogen bonds, so there is nothing for heat to break
- D. active sites that no longer depend on the enzyme's shape
Correct answer: B. Extra stabilizing interactions resist the heat that breaks H-bonds and causes denaturation.
Enzyme and substrate are mixed in a test tube. The rate slows over 30 minutes, though the enzyme is still fully active when tested afterward. The best explanation is that
- A. the enzyme is slowly denatured by the reaction it catalyzes
- B. the temperature of the tube rises above the enzyme's optimum
- C. substrate is being used up and product is building up ✓
- D. the enzyme is consumed and must be replaced by the cell
Correct answer: C. Relative concentrations of substrate and product set how efficiently the reaction proceeds (3.2.B.1).
If the cell constantly pumps D out so that D never builds up, what is the most likely result?
- A. Enzyme 3 stops working because it has no product left
- B. Enzyme 1 is inhibited more strongly and A builds up
- C. Substance A is converted straight into D, skipping B and C
- D. Enzyme 1 stays active and B, C and D keep being made ✓
Correct answer: D. Without D to inhibit enzyme 1 allosterically, feedback inhibition is lost and the pathway keeps running.